Count Total Even Numbers in Series of 10 Numbers using 8085

In this program we will see how to count number of even numbers in a block of elements.

Problem Statement

Write 8085 Assembly language program to count number of even numbers in a block of data, where the block size is 10D. The block is starting from location8000H.

Discussion

The Odd Even checking is very simple. we can determine one number is odd or even by checking only the LSb. When LSb is 1, the number is odd, otherwise it is even. In this program we are taking a number from memory and then ANDing01H with it. if the result is nonzero, then the number is odd, otherwise it is even.

Input

Address
 Data
.
.
.
 .
.
.
8000
 DA
8001
 53
8002
 26
8003
 41
8004
 17
8005
 AC
8006
 78
8007
 D8
8008
 9C
8009
 3F
.
.
.
 .
.
.


Flow Diagram

Program

Address
 HEX Codes
 Labels
 Mnemonics
 Comments
F000
 21, 00, 80

LXI H,8000H
 Point to the starting byte
F003
 0E, 0A

MVI C,0AH
 Initialize count to 0AH
F005
 06, 00

MVI B, 00H
 Clear B register
F007
 7E
 LOOP
 MOV A,M
 Load the item from memory
F008
 E6, 01

ANI 01H
 AND A with01H
F00A
 C2, 0E, F0

JNZ SKIP
 If Z = 1, jump to skip
F00D
 04

INR B
 Increase B by1
F00E
 23
 SKIP
 INX H
 Point to next location
F00F
 0D

DCR C
 Decrease C by1
F010
 C2, 07, F0

JNZ LOOP
 if Z = 0, goto loop
F013
 78

MOV A, B
 Load the count to A
F014
 32, 50, 80

STA 8050H
 Store the result at 8050H
F017
 76

HLT
 Terminate the program


Output

Address
 Data
.
.
.
 .
.
.
8050
 06
.
.
.
 .
.
.
Updated on: 2019-07-30T22:30:24+05:30

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