Find Maximum of Two 8-Bit Numbers in 8085

In this program we will see how to find the maximum of two numbers.

Problem Statement

Write 8085 Assembly language program to find the maximum number of two 8-bit number stored at location 8000H and 8001H.

Discussion

This checking is done by using the CMP instruction. This instruction is very similar to the SUB instruction. The only difference is that it does not update the value of Accumulator after executing. So after comparing, if the CY flag is set, it means that the first number is smaller, and the second one is larger

Input

First input

Address
 Data
.
.
.
 .
.
.
8000
 FD
8001
 23
.
.
.
 .
.
.

second input

Address
 Data
.
.
.
 .
.
.
8000
 59
8001
 75
.
.
.
 .
.
.


Flow Diagram

Program

Address
 HEX Codes
 Label
 Mnemonics
 Comments
F000
 21, 00, 80

LXI H, 8000H
 Point to the first number
F003
 46

MOV B,M
 Load the first number to B
F004
 23

INX H
 Point to next location
F005
 7E

MOV A,M
 Get the second number to A
F006
 B8

CMP B
 Compare B with A
F007
 D2, 0B, F0

JNC STORE
 Is CY = 0,jump to Store
F00A
 78

MOV A,B
 Load A with second number
F00B
 32, 50, 80
 STORE
 STA 8050H
 Store the number into memory
F00E
 76

HLT
 Terminate the program


Output

First output

Address
 Data
.
.
.
 .
.
.
8050
 FD
.
.
.
 .
.
.


Second output

Address
 Data
.
.
.
 .
.
.
8050
 75
.
.
.
 .
.
.
Updated on: 2019-07-30T22:30:24+05:30

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