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Swap Two 8-Bit Numbers Using Direct Addressing Mode in 8085
In this program we will see how to swap two numbers in direct addressing mode.
Problem Statement
Write 8085 Assembly language program to swap two 8-bit number stored at location 8000H and 8001H using direct addressing mode.
Discussion
In this case we are taking the number from memory by using the HL pair. The HL pair is storing the address of the data item. We are taking the first number into B register, and the second number to A register, then storing the content of B to the next position, and storing the value of A into first position.
Input
| Address |
Data |
|---|---|
| . . . |
. . . |
| 8000 |
CD |
| 8001 |
34 |
| . . . |
. . . |
Flow Diagram
Program
| Address |
HEX Codes |
Mnemonics |
Comments |
|---|---|---|---|
| F000 |
21, 00, 80 |
LXI H,8000H |
Point to the first number |
| F003 |
46 |
MOV B,M |
Load the first number to B |
| F004 |
23 |
INX H |
Point to the next number |
| F005 |
7E |
MOV A,M |
Load the second number into A |
| F006 |
70 |
MOV M,B |
Store first number to second position |
| F007 |
2B |
DCX H |
Point to previous location |
| F008 |
77 |
MOV M,A |
Store second number to first position |
| F009 |
76 |
HLT |
Terminate the program |
Output
| Address |
Data |
|---|---|
| . . . |
. . . |
| 8000 |
34 |
| 8001 |
CD |
| . . . |
. . . |
Updated on: 2019-07-30T22:30:24+05:30
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