Find Odd and Even Numbers in an Array in Java

In the loop check, the result of i%2 operation on each element if 0 the element is even else the element is odd.

Example

Live Demo

public class OddNumbersInAnArray {
   public static void main(String args[]) {
      int[] myArray = {23, 93, 56, 92, 39};
      System.out.println("Even numbers in the given array are:: ");
      for (int i=0; i<myArray.length; i++) {
         if(myArray[i]%2 == 0) {
            System.out.println(myArray[i]);
         }
      }
      System.out.println("Odd numbers in the given array are:: ");
      for (int i=0; i<myArray.length; i++) {
         if(myArray[i]%2 != 0) {
            System.out.println(myArray[i]);
         }
      }
   }
}

Output

Even numbers in the given array are::
56
92
Odd numbers in the given array are::
23
93
39