Check If Given Matrix Is a Magic Square in C++

Here we will see, if a matrix is magic square or not, a magic square is a square matrix, where the sum of each row, each column, and each diagonal are same.

Suppose a matrix is like below −

This is a magic square, if we see, the sum of each row, column and diagonals are 15.

To check whether a matrix is magic square or not, we have to find the major diagonal sum and the secondary diagonal sum, if they are same, then that is magic square, otherwise not.

Example

 Live Demo

#include <iostream>
#define N 3
using namespace std;
bool isMagicSquare(int mat[][N]) {
   int sum_diag = 0,sum_diag_second=0;
   for (int i = 0; i < N; i++)
      sum_diag = sum_diag + mat[i][i];
   for (int i = 0; i < N; i++)
      sum_diag_second = sum_diag_second + mat[i][N-1-i];
   if(sum_diag!=sum_diag_second)
      return false;
   for (int i = 0; i < N; i++) {
      int rowSum = 0;
      for (int j = 0; j < N; j++)
         rowSum += mat[i][j];
      if (rowSum != sum_diag)
         return false;
   }
   for (int i = 0; i < N; i++) {
      int colSum = 0;
      for (int j = 0; j < N; j++)
         colSum += mat[j][i];
      if (sum_diag != colSum)
      return false;
   }
   return true;
}
int main() {
   int mat[][N] = {{ 6, 1, 8 },
   { 7, 5, 3 },
   { 2, 9, 4 }};
   if (isMagicSquare(mat))
      cout << "It is Magic Square";
   else
   cout << "It is Not a magic Square";
}

Output

It is Magic Square