Check If All Elements of the Array Are Palindrome in Python

Suppose we have a list of numbers nums. We have to check whether the list is palindrome or not.

So, if the input is like nums = [10, 12, 15, 12, 10], then the output will be True.

To solve this, we will follow these steps −

• n := size of nums
• reset is_palindrome
• i := 0
• while i <= quotient of (n / 2) and n is not 0, do
  • if nums[i] is not same as nums[n - i - 1], then
    • set is_palindrome
    • come out from the loop
  • i := i + 1
• if is_palindrome is set, then
  • return False
• otherwise,
  • return True

Let us see the following implementation to get better understanding −

Example

 Live Demo

def solve(nums):
   n = len(nums)
   is_palindrome = 0
   i = 0
   while i <= n // 2 and n != 0:
      if nums[i] != nums[n - i - 1]:
         is_palindrome = 1
         break
      i += 1
   if is_palindrome == 1:
      return False
   else:
      return True
nums = [10, 12, 15, 12, 10]
print(solve(nums))

Input

[10, 12, 15, 12, 10]

Output

True