Check if All Occurrences of a Character Appear Together in Python

Suppose we have a string s and another character c, we have to check whether all occurrences of c appear together in s or not. If the character c is not present in s then also return true.

So, if the input is like s = "bbbbaaaaaaaccddd", c = 'a', then the output will be True.

To solve this, we will follow these steps −

• flag := False
• index := 0
• n := size of string
• while index < n, do
  • if string[index] is same as c, then
    • if flag is True, then
      • return False
    • while index < n and string[index] is same as c, do
      • index := index + 1
    • flag := True
  • otherwise,
    • index := index + 1
• return True

Let us see the following implementation to get better understanding −

Example

 Live Demo

def solve(string, c) :
   flag = False
   index = 0
   n = len(string)
   while index < n:
      if string[index] == c:
         if (flag == True) :
            return False
         while index < n and string[index] == c:
            index += 1
         flag = True
      else :
         index += 1
   return True
s = "bbbbaaaaaaaccddd"
c = 'a'
print(solve(s, c))

Input

"bbbbaaaaaaaccddd", "a"

Output

True