C++ Program for Smallest K-Digit Number Divisible by X

In this problem we will try to find smallest K-digit number, that will be divisible by X. To do this task we will take the smallest K digit number by this formula (10^(k-1)). Then check whether the number is divisible by X or not, if not, we will get the exact number by using this formula.

(min+ ?)−((min+ ?) ??? ?)

One example is like a 5-digit number, that is divisible by 29. So the smallest 5-digit number is 10000. This is not divisible by 29. Now by applying the formula we will get −

(10000+ 29)−((10000+29) ??? 29)=10029−24=10005

The number 10005 is divisible by 29.

Algorithm

minKDigit(k, x)

begin
   min = 10 ^ (k-1)
   if min is divisible by x, return min
   otherwise return (min + x) – ((min + x) mod x)
end

Example

 Live Demo

#include<iostream>
#include<cmath>
using namespace std;
long min_k_digit(int k, int x) {
   //get the minimum number of k digits
   int min = pow(10, k-1);
   if(min % x == 0) {
      return min;
   }
   return (min + x) - ((min + x) % x);
}
main() {
   int k, x;
   cout << "Enter Digit Count(K) and Divisor(N): ";
   cin >> k >> x;
   cout << "Result is: " << min_k_digit(k, x);
}

Output

Enter Digit Count(K) and Divisor(N): 5 29
Result is: 10005

Output

Enter Digit Count(K) and Divisor(N): 6 87
Result is: 100050