Find Number of Players Rolling the Dice in C++

Suppose we have a string S and a number X. There are M different players who roll the dice. one player keeps on rolling the dice until he gets a number other than X. Here in the string S, S[i] represents the number at ith roll of a dice. We have to find the value of M. One constraint is that the last character in S will never be X. So for example, if string is “3662123” and X = 6, the output will be 5. This can be described as follows −

• First player rolls and got 3
• Second player rolls, and got 6, 6 and 2
• Third player rolls, and got 1
• Fourth player rolls, and got 2
• Fifth player rolls, and got 3

The task is simple, we will traverse the string, and count the number of characters, that are not X, the count will be the answer.

Example

 Live Demo

#include<iostream>
using namespace std;
int countPlayers(string str, int x) {
   int count = 0;
   for (int i = 0; i < str.size(); i++) {
      if (str[i] - '0' != x)
      count++;
   }
   return count;
}
int main() {
   string s = "3662123";
   int x = 6;
   cout << "Number of players: " << countPlayers(s, x);
}

Output

Number of players: 5