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Delete Last Node from a Linked List in Golang
Examples
Approach to solve this problem −
Step 1 − Define a method that accepts the head of a linked list.
Step 2 − If head == nil, return the head.
Step 3 − Go to the next node and return the updated head.
Example
package main import ( "fmt" ) type Node struct { value int next *Node } func NewNode(value int, next *Node) *Node{ var n Node n.value = value n.next = next return &n } func TraverseLinkedList(head *Node){ temp := head for temp != nil { fmt.Printf("%d ", temp.value) temp = temp.next } fmt.Println() } func DeleteLastNode(head *Node) *Node{ if head == nil{ return head } temp := head for temp.next.next != nil{ temp = temp.next } temp.next = nil return head } func main(){ head := NewNode(30, NewNode(10, NewNode(40, NewNode(40, nil)))) fmt.Printf("Input Linked list is: ") TraverseLinkedList(head) head = DeleteLastNode(head) fmt.Printf("After deleting last node of the linked list: ") TraverseLinkedList(head) }
Output
Input Linked list is: 30 10 40 40 After deleting last node of the linked list: 30 10 40
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