Print All Combinations of Points that Can Compose a Given Number in C++

In this problem, we are given the total score n. Print all combinations of basketball points that are 1, 2, and 3 that give a total score of n.

Let’s see an example to understand the problem,

Input: 4
Output:
1 1 1 1
1 1 2
1 2 1
1 3
2 1 1
2 2
3 1

To solve this problem, we will use recursion. And fix and resources for rest values n-s, where s is the score. If the combination adds up to n, print the combination.

Example

The code shows the implementation of our code −

 Live Demo

#define MAX_POINT 3
#define ARR_SIZE 100
#include <bits/stdc++.h>
using namespace std;
void printScore(int arr[], int arr_size) {
   int i;
   for (i = 0; i < arr_size; i++)
      cout<<arr[i]<<" ";
   cout<<endl;
}
void printScoreCombination(int n, int i) {
   static int arr[ARR_SIZE];
   if (n == 0) {
      printScore(arr, i);
   }
   else if(n > 0) {
      int k;
      for (k = 1; k <= MAX_POINT; k++){
         arr[i]= k;
         printScoreCombination(n-k, i+1);
      }
   }
}
int main() {
   int n = 4;
   cout<<"Different compositions formed by 1, 2 and 3 of "<<n<<" are\n";
   printScoreCombination(n, 0);
   return 0;
}

Output

Different compositions formed by 1, 2 and 3 of 4 are
1 1 1 1
1 1 2
1 2 1
1 3
2 1 1
2 2
3 1