Find Total Duration of K Most Watched Shows in Python

Suppose we have a list of list of strings called shows, also have a list of integers called durations, and another value k, here shows[i] and durations[i] represent a show and its duration watched by the ith man, we have to find the total duration watched of the k most watched shows.

So, if the input is like shows = ["The BGT", "Jack jumper", "The BGT", "Jokers Company", "Music magic"] durations = [10, 8, 10, 18, 9] k = 2, then the output will be 38, as the top 2 most watched shows are "Jokers Company" and "The BGT" and total durations is 18 and 10 + 10 = 20.

To solve this, we will follow these steps −

• if shows is empty or durations is empty or k is 0, then

  • return 0

• d := an empty dictionary

• for i in range 0 to size of shows, do

  • d[shows[i]] := d[shows[i]] + durations[i]

• l := a new list

• for each i in d, do

  • insert d[i] at the end of l

• sort the list l in reverse order

• i := 0

• answer := 0

• while i < k, do

  • answer := answer + l[i]

  • i := i + 1

• return answer

Example

Let us see the following implementation to get better understanding

from collections import defaultdict
def solve(shows, durations, k):
   if not shows or not durations or not k:
      return 0

   d = defaultdict(int)

   for i in range(len(shows)):
      d[shows[i]] += durations[i]

   l = []
   for i in d:
      l.append(d[i])
   l.sort(reverse=True)
   i = 0
   answer = 0
   while i < k:
      answer += l[i]
      i += 1
   return answer

shows = ["The BGT", "Jack jumper", "The BGT", "Jokers Company",
"Music magic"]
durations = [10, 8, 10, 18, 9]
k = 2
print(solve(shows, durations, k))

Input

["The BGT", "Jack jumper", "The BGT", "Jokers Company", "Music magic"], [10, 8, 10, 18, 9], 2

Output

38