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Return a Sorted Copy of the Index in Descending Order in Python Pandas
To return a sorted copy of the index, use the index.sort_values() method in Pandas. The parameter ascending is set False.
At first, import the required libraries −
import pandas as pd
Creating Pandas index −
index = pd.Index([50, 10, 70, 95, 110, 90, 30])
Display the Pandas index −
print("Pandas Index...\n",index)
Sort index values. To sort values in Descending order, set the "ascending" parameter to "False" −
print("\nSort the index values in descending order...\n",index.sort_values(ascending=False))
Example
Following is the code −
import pandas as pd # Creating Pandas index index = pd.Index([50, 10, 70, 95, 110, 90, 30]) # Display the Pandas index print("Pandas Index...\n",index) # Return the number of elements in the Index print("\nNumber of elements in the index...\n",index.size) # Return the dtype of the data print("\nThe dtype object...\n",index.dtype) # Sort index values # To sort values in Descending order, set the "ascending" parameter to "False" print("\nSort the index values in descending order...\n",index.sort_values(ascending=False))
Output
This will produce the following output −
Pandas Index... Int64Index([50, 10, 70, 95, 110, 90, 30], dtype='int64') Number of elements in the index... 7 The dtype object... int64 Sort the index values in descending order... Int64Index([110, 95, 90, 70, 50, 30, 10], dtype='int64')
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