Second Most Repeated Word in a Sequence in Python

The string is given, our task is to find out the second repeated word. Here we Counter(iterator) for creating dictionary which contains word as key and its frequency as value.

Algorithm

Step 1: Create user define list.
Step 2: Then convert list into a dictionary.
Step 2: Next get the values and sort them in descending order.
Step 3: Then the second element is the second largest value.
Step 4: Next again traverse whole dictionary and display key whose value is equal to second largest element.

Example code

# To print Second most repeated word in a sequence in Python from collections 
import Counter
defsecondrepeatation(A):
# Convert list into dictionary
con = Counter(A)
res = sorted(con.values(), reverse=True)
maxi = res[1]
for (key, val) in con.items():
   if val == maxi:
       print("Second most repeated word ::>",key)
       return
# Driver program
if __name__ == "__main__":
   A=list()			#create user defined list
n=int(input("Enter the size of the List ::"))
print("Enter the word ::")
for i in range(int(n)):
   k=input("")
   A.append(k)
secondrepeatation(A)		# call function

Output

Enter the size of the List ::4
Enter the word ::
aa
bb
aa
cc
Second most repeated word ::> bb