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Sort Array in Waveform Using Python
In this article, we will learn a python program to sort an array in the waveform.
Assume we have taken an unsorted input array. We will now sort the input array in a waveform. An array ?arr[0..n-1]' is sorted in wave form if arr[0] >= arr[1] <= arr[2] >= arr[3] <= arr[4] >= ?..
Methods Used
The following are the various methods used to accomplish this task &miinus;
Using Built-in sort() function
Without Using Built-in functions
Method 1: Using the Built-in sort() function
Algorithm (Steps)
Following are the Algorithms/steps to be followed to perform the desired task. ?
Create a function to sort the array in waveform by accepting the input array, and array length as arguments.
Use the sort() function(sorts the list in ascending/descending order ) to sort the input array in ascending order.
Use the for loop to traverse till the array length alternatively(step=2)
Swap the adjacent elements i.e, current and its next using the ?,' operator.
Create a variable to store the input array.
Use the len() function(returns the number of items in an object) to get the length of an input array.
Call the above-defined sortingInWaveform() function by passing the input array, and length of the array as arguments
Use the for loop to traverse through all the elements of an array
Print the current element of an array.
Example
The following program sorts the input array in waveform using the python Built-in sort() function ?
# creating a function to sort the array in waveform by accepting # the input array, array length as arguments def sortingInWaveform(inputArray, arrayLength): # sorting the input array in ascending order using the sort() function inputArray.sort() # travsersing till the array length alternatively(step=2) for k in range(0, arrayLength-1, 2): # swapping the adjacent elements i.e, current and it's next inputArray[k], inputArray[k+1] = inputArray[k+1], inputArray[k] # input array inputArray = [12, 45, 15, 4, 6, 70, 68, 3, 25] # getting the length of the input array arrayLength = len(inputArray) # printing the given array/list print("The Given list is:", inputArray) # calling the above defined sortingInWaveform() function by # passing input array, length of the array as arguments sortingInWaveform(inputArray, arrayLength) print("The Result Array after sorting in wave form is:") # traversing through all the elements of the array for k in range(0, arrayLength): # printing the current element of the array/list print(inputArray[k], end=" ")
Output
On execution, the above program will generate the following output &miinus;
The Given list is: [12, 45, 15, 4, 6, 70, 68, 3, 25] The Result Array after sorting in wave form is: 4 3 12 6 25 15 68 45 70
Time complexity ? O(nLogn).
Here, the array that was given was sorted using the sort function, which typically has an O(NlogN) time complexity.
If an O(nLogn) sorting algorithm like Merge Sort, Heap Sort, etc. is applied, the above-given method has an O(nLogn) time complexity.
Method 2: Using Only One Loop
Algorithm (Steps)
Following are the Algorithms/steps to be followed to perform the desired task. ?
Use the for loop to traverse through all the even index elements by passing 0, array length, and step value as arguments
Use the if conditional statement to check whether the current even index element is smaller than the previous.
Swap the elements if the condition is true.
Use the if conditional statement to check whether the current even index element is smaller than the next element.
Swap the elements if the condition is true.
Call the above-defined sortingInWaveform() function by passing the input array, and length of the array as arguments
Use the for loop, to traverse through the elements of the array.
Print the corresponding element of the array/list.
Example
The following program sorts the input array in wave form using only one for loop and without Built-in functions ?
# creating a function to sort the array in waveform by accepting # the input array, array length as arguments def sortingInWaveform(inputArray, arrayLength): # traversing through all the even index elements for p in range(0, arrayLength, 2): # checking whether the current even index element # is smaller than the previous if (p > 0 and inputArray[p] < inputArray[p-1]): # swapping the elements if the condition is true inputArray[p], inputArray[p-1] = inputArray[p-1], inputArray[p] # checking whether the current even index element # is smaller than the next element if (p < arrayLength-1 and inputArray[p] < inputArray[p+1]): # swapping the elements if the condition is true inputArray[p], inputArray[p+1] = inputArray[p+1], inputArray[p] # input array inputArray = [12, 45, 15, 4, 6, 70, 68, 3, 25] # getting the length of the input array arrayLength = len(inputArray) print("The Given list is:", inputArray) # calling the above defined sortingInWaveform() function by # passing input array, length of the array as arguments sortingInWaveform(inputArray, arrayLength) print("The Result Array after sorting in wave form is:") # traversing through all the elements of the array for k in range(0, arrayLength): # printing the current element print(inputArray[k], end=" ")
Output
On execution, the above program will generate the following output ?
The Given list is: [12, 45, 15, 4, 6, 70, 68, 3, 25] The Result Array after sorting in wave form is: 45 12 15 4 70 6 68 3 25
Time complexity ? O(n).
Here, we didn't use the sort function; instead, we just used the for loop to iterate through the elements of the given array, which, on average, has O(N) time complexity.
Conclusion
In this article, we learned how to sort the given waveform array using two different methods. A new logic that has a reduced O(log N) time complexity than the first way is what we used to reduce the time complexity. In many situations, these kinds of algorithms are helpful to lessen the time complexities and carry out effective solutions.