[ruby-core:95467] [Ruby master Bug#16270] Strange behavior on Hash's #each and #select method.
From:
vil963@...
Date:
2019-10-22 16:13:56 UTC
List:
ruby-core #95467
Issue #16270 has been reported by zw963 (Wei Zheng).
----------------------------------------
Bug #16270: Strange behavior on Hash's #each and #select method.
https://bugs.ruby-lang.org/issues/16270
* Author: zw963 (Wei Zheng)
* Status: Open
* Priority: Normal
* Assignee:
* Target version:
* ruby -v: 2.6.3
* Backport: 2.5: UNKNOWN, 2.6: UNKNOWN
----------------------------------------
Following is some example code:
``` ruby
sample_hash = {
"246" => {
"price" => "8000",
"note" => ""
},
"247" => {
"price" => "8000",
"note" => ""
},
"248" => {
"price" => "8000",
"note" => ""
}
}
sample_hash.each {|e| p e}
# following is p output content, we can see e is a hash element, and convert to a array object.
# this is expected behavior maybe, anyway, hash is same as a nested array.
["246", {"price"=>"8000", "note"=>""}]
["247", {"price"=>"8000", "note"=>""}]
["248", {"price"=>"8000", "note"=>""}]
sample_hash.select {|e| p e }
# Wired, why this time, e output different with each?
"246"
"247"
"248"
```
Following is source code for **each**
```c
static VALUE
rb_hash_each_pair(VALUE hash)
{
RETURN_SIZED_ENUMERATOR(hash, 0, 0, hash_enum_size);
if (rb_block_arity() > 1)
rb_hash_foreach(hash, each_pair_i_fast, 0);
else
rb_hash_foreach(hash, each_pair_i, 0);
return hash;
}
```
Following is source code for **select**
```c
VALUE
rb_hash_select(VALUE hash)
{
VALUE result;
RETURN_SIZED_ENUMERATOR(hash, 0, 0, hash_enum_size);
result = rb_hash_new();
if (!RHASH_EMPTY_P(hash)) {
rb_hash_foreach(hash, select_i, result);
}
return result;
}
```
I don't understand C well, don't know why lack of consistency for above two Hash method,
but, i think it is a little confuse me.
Thank you.
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