Documentation: Generate enum name for flags

The actual flags name is not used, it is merely an alias in the type
dict.

Fixes: PYSIDE-2539
Pick-to: 6.6
Change-Id: Id7f5c8236091790ac9c10595787b86471e300065
Reviewed-by: Shyamnath Premnadh <[email protected]>

1 files changed, 7 insertions, 0 deletions

diff --git a/sources/shiboken6/generator/qtdoc/qtdocgenerator.cpp b/sources/shiboken6/generator/qtdoc/qtdocgenerator.cpp
index faa3fb8a3..f95fe489d 100644
--- a/sources/shiboken6/generator/qtdoc/qtdocgenerator.cpp
+++ b/sources/shiboken6/generator/qtdoc/qtdocgenerator.cpp
@@ -25,6 +25,7 @@
 #include <functiontypeentry.h>
 #include <enumtypeentry.h>
 #include <complextypeentry.h>
+#include <flagstypeentry.h>
 #include <primitivetypeentry.h>
 #include <qtdocparser.h>
 #include <doxygenparser.h>
@@ -719,6 +720,12 @@ QString QtDocGenerator::translateToPythonType(const AbstractMetaType &type,
     if (found != typeMap.cend())
         return found.value();
 
+    if (type.isFlags()) {
+        const auto fte = std::static_pointer_cast<const FlagsTypeEntry>(type.typeEntry());
+        auto enumName = fte->originator()->targetLangName();
+        return "Combination of "_L1 + (createRef ? toRef(enumName) : enumName);
+    }
+
     if (type.isConstant() && name == "char"_L1 && type.indirections() == 1)
         return "str"_L1;