[Dev-C++] how come n+1 = *(n+1) ????

read the program below and the question.i am not able to understand how it is
happening.your help is appreciated.

#include <stdio.h>

int main()
{int n[5][2]={
               {0,1},
               {2,3},
               {4,5},
               {6,7},
               {8,9}
             };
printf("\n%u",&n[1][0]);
printf("\n%u",n+1);
printf("\n%u",*(n+1));

      system("PAUSE");
      return 0;
}                       /*QUESTION) while it is apparent that n+1 will give
                           the address of n[1][0] but how come *(n+1) also
                           gives the address of n[1][0]

                           instead of n+1 & *(n+1) u can take n+i & *(n+i)
                           for i=0 to i=4  */

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