RE: [Dev-C++] sizeof array

> -----Original Message-----
> From: Ramana Kumar [mailto:ra...@my...] 
> Sent: Wednesday, July 31, 2002 2:19 PM
> To: Ioannis Vranos; C++
> Subject: RE: [Dev-C++] sizeof array
> 
> 
> thanks ioannis, i have briefly read your reply and it is what 
> i had feared.
> is there any way to implement what i had before so that the 
> sizeof operator
> reports the size as if it were a local array? for example, 
> can i pass the
> array to the function by reference or dereference the pointer that is
> passed?


No there is no way for a built in array. The only thing you can do, is
pass an additional argument, the size of the array in the style


void f(char *s[], const unsigned long SIZE);


Or better, use some standard library container, such as vector.


Ioannis

* Ioannis Vranos
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