Re: [Dev-C++] array of strings

More than useful, thank you fellow :-)


>Here I send you an example of
>a string array resizing on-the-fly  as you require...
>This possible solution is built with the
>"realloc( )" function as you indicated in
>your message.
>
>I hope this example illuminates your way toward
>a peaceful programming...Salam alecum!!.
>Ricardo.
>
>
>*******************PROGRAM*******************
>/* ALLOCATING AND REALLOCATING MEMORY */
>#include <stdio.h>
>#include <stdlib.h>
>
>int main()
>{
>    char **p;
>    int N,i;
>
>    printf("Give me the initial array string dimension: ");
>    scanf("%d", &N);
>    fflush(stdin);
>
>  /* As you want your initial array dimension is given
>     by the user and it is allocated in this way */
>
>    p= (char **)realloc(NULL,N*sizeof(char*));
>    for(i=0; i<N ; i++)
>    {
>       /*strings of 10 char */
>       p[i]= (char*)realloc(NULL,10*sizeof(char));
>       printf("dame string %d: ",i);
>       gets(p[i]);
>       puts(p[i]);
>    }
>
>    /* if you need to store still more array strings
>       you can reuse the reallocate function as follows */
>
>    printf("Give me the new array string dimension: ");
>    scanf("%d",&N);
>    fflush(stdin);
>
>    p= (char **)realloc(p,N*sizeof(char*));
>    for(i=i; i<N ; i++)
>    {
>       p[i]= (char*)realloc(NULL,10*sizeof(char));
>       printf("dame string %d: ",i);
>       gets(p[i]);
>       puts(p[i]);
>    }
>
>    /* Verification of correct string storing */
>    printf("\n\n");
>    for(i=0; i<N ; i++) puts(p[i]);
>
>    /* At the end it is convenient to free the memory */
>    for(i=0; i<N ; i++) free(p[i]);
>    free(p);
>
>      system("PAUSE");
>      return 0;
>}
>
>*****************************
>


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