Re: [Dev-C++] Manipulator

char* is more difficult, since there's a specific overload for it that 
prints a string. I suppose you could cast it to a long and print that. 
Bit ugly, though.

char * str;
cout << hex << reinterpret_cast<long>(str) << endl;

By the way, my earlier answer could be even simpler:

int var;
cout << &var << endl;   // still prints in hex.

Graham

Esteban Valverde wrote:

>What a dummy !!! thanks... and what about char * ?
>
>char * str;
>...
>cout << hex << str 
>
>doesn't works.
>
>
>Esteban
>
>
>----- Original Message ----- 
>From: "Graham Douglas" <g.d...@nt...>
>To: "Esteban Valverde" <est...@ho...>
>Sent: Tuesday, 29 July, 2003 16:24
>Subject: Re: [Dev-C++] Manipulator
>
>
>cout << hex << &var << endl;
>
>
>
>  
>