Re: [Dev-C++] Converting macro to inline function.

The only way I can think of is change the original macro call to call the
function instead, ie:
#define CREATE(result,type,number) createf<type>(result,number)

At 07:22 AM 23/12/2003 -0800, David McKen wrote:
>I am cleaing up some code and came across the following macro:
>
>#define CREATE(result, type, number)  \
>do  \
>{  \
>  if (!((result) = (type *) calloc ((number), sizeof(type)))) \
>  { \
>   perror("malloc failure");               \
>   fprintf(stderr, "Malloc failure @ %s:%d\n", __FILE__, __LINE__ );
>\
>   abort();                        \
>  }                               \
>} while(0)
>
>I want to convert to a function (most likely inline, its small
>enough) the problme I am having is with the second parameter, it is a
>data type!
>
>So far the following seems like it would work:
>
>template<class type>
>inline void CREATE(result, number)
>{
>  if (!((result) = (type *) calloc ((number), sizeof(type))))
>  {
>   perror("malloc failure");
>   fprintf(stderr, "Malloc failure @ %s:%d\n", __FILE__, __LINE__ );
>   abort();
>  } 
>}
>
>The problem is this macro is quite heavily used. Changing the
>function to the following would require me to change the "macro call"
>to the following function call:
>
>CREATE<int>(pToSomewhere, 500); //To create 500 ints.
>
>Is there around this or will I also have to change all the function
>calls?
>
>Thanks in Advance.
>David McKen
>
>P.S. I am lazy, I admit it. I don't want to change all those lines of
>code, if I have to so be it. I am changing this macro to a function.
>
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