Re: [Dev-C++] std streams and enum?

Hi Maya,

Sorry if a little bit late!

> Can someone please help me?
> I am using an enum type that I want to store in a std::IOStream object, 
> but the compiler [complainer] tells me that the format is not supported. 
> enum types are the same as 'const int' right? 

Nope! They are not. I checked the Standard and found out that,
in Section 7.2 (Enumeration Decleration) #5, it says that the
underlying type of an enumeration is an integeral type that is
implementation-specific. It doesn't mention anything about
whether it is a const-qualified type or not. Nor does it mention
anything about whether there must be just one candidate
underlying type for a given enum type or are two or more
candidates possible as well.

> namespace jme{
> enum account_t {Zero, One, Two};
> class Account{
> protected:
>     account_t type;
> 
>     ....
> public:
>     friend std::istream&
>        jme::operator>>(std::istream& is, jme::Account& obj){
>            is >> obj.type;  // <<======== Here is the problem ****
>            return is;
>        }
> };
> }
> This gives me an error that reads:
> ====================================================
> account.H: In function `std::istream& jme::operator>>(std::istream&,
>     jme::Account&)':
> account.H:91: no match for `std::basic_istream<char, 
> std::char_traits<char> >&
>     >> jme::account_t&' operator <<<<<<<====== This is the problem *****
> ...: candidates are:
> 
> /* Gives me a list of other candidates */
> 
> ====================================================

Considering the above citations from the Standard, it seems that
your compiler has found itself not knowing which type to choose
as the underlying type. I think the best solution is to choose
one and clarify it in a way that the compiler understands it.

Furthermore, that long error comment from your compiler is just
'cause it's trying to use the default streaming tools.

Regards,
--Hossein
-- 
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