Re: [Dev-C++] Getting the wrong output

hi...

you should remove the std:: before operator:

--- Money.hpp
friend ostream& std::operator<<( std::ostream&, const jme::Money& );
friend istream& std::operator>>( std::istream&, jme::Money& );


--- Money.cpp
operator<<( std::ostream& os, const jme::Money& obj ) {
    os << obj.getAmount();
    return os;
}
std::istream&
operator>>( std::istream& is, jme::Money& obj ) {
    is >> obj.amount;
    return is;
}




>Yes, I just notice that, so this are the changes I have made:
>
>--- Money.hpp
>friend std::ostream& std::operator<<( std::ostream&, const jme::Money& );
>friend std::istream& std::operator>>( std::istream&, jme::Money& );
>
>
>--- Money.cpp
>std::operator<<( std::ostream& os, const jme::Money& obj ) {
>    os << obj.getAmount();
>    return os;
>}
>std::istream&
>std::operator>>( std::istream& is, jme::Money& obj ) {
>    is >> obj.amount;
>    return is;
>}
>--------------
>But this is giving me linker errors sayng:
>
>
>=========  ERROR ===========
>In file included from money.cpp:2:
>money.hpp:67: error: `std::ostream& std::operator<<(std::ostream&, const
>jme::Money&)' should have been declared inside `std'
>money.hpp:68: error: `std::istream& std::operator>>(std::istream&,
>jme::Money&)' should have been declared inside `std'
>
>
>What am I doing wrong!!?
>
>Again thanks for you help.
>
>
>
>
>  
>
>>What namespaces are you using.
>>
>>You have declared the friend operator as:
>>  std::ostream& operator<<(...)
>>and implemented it as:
>>  std::ostream& jme::operator<<(...)
>>
>>Without a maching output operator, the compiler will emit the pointer to
>>the object instead.
>>
>>/Per W
>>
>>On Thu, 30 Jun 2005 jal...@go... wrote:
>>
>>    
>>
>>>In my class, when I use the "getter" to display the value I get the
>>>right
>>>output, but when I try using the overloaded extractor operator (<<) I
>>>get
>>>some hex value displayed. Here is some of the code:
>>>--- snip
>>>Main.cpp
>>>int main() {
>>>   Money money("12.21");
>>>
>>>   std::cout << "Value is: " << money.getAmount() << std::endl; // 12.21
>>>   std::cout << "Value is: " << money << std::endl; // hex value????
>>>   return 0;
>>>}
>>>
>>>
>>>
>>>The class goes like this:
>>>---snip
>>>Money.hpp
>>>class Money {
>>> protected:
>>>   float amount;    //!< This variable holds the numerical value
>>> public:
>>>   //! Constor
>>>   Money(const std::string&);
>>>
>>>   //!Copy constructor
>>>   Money( const Money& );
>>>
>>>   //!Destructor
>>>   ~Money() { std::cout << amount << std::endl;} //<<=== 12.21
>>>
>>>   // Setters
>>>   ...
>>>   // Getters
>>>   const float getAmount() const;
>>>
>>>   // Overloaded operators
>>>   .....
>>>   friend std::ostream& operator<<( std::ostream&, const jme::Money& );
>>>   friend std::istream& operator>>( std::istream&, jme::Money& );
>>>   ....
>>>} ; //Money
>>>
>>>
>>>
>>>and the code looks like this
>>>--- snip
>>>jme::Money::Money( const std::string& x){
>>>    this->setAmount(x); // this metho converts the std::string to a
>>>float
>>>}
>>>const float jme::Money::getAmount() const {
>>>    return this->amount;
>>>}
>>>std::ostream&
>>>jme::operator<<( std::ostream& os, const jme::Money& obj ) {
>>>    os << obj.getAmount(); //<<==== 0x4b1120
>>>    return os;
>>>}
>>>----- end of snip
>>>As you can see when using the member method getAmount() the value
>>>displayed is in the right format, however the extractor operator is not
>>>doing
>>>      
>>>
>>
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>>    
>>
>
>
>
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