|
From: Josh M. <mrl...@gm...> - 2005-10-31 04:13:45
|
pow( [base number], [exponent] ) pow( 2, 3 ) =3D=3D 8 =3D=3D 2^3 (where ^ represents exponent, not exclusive= or) pow( 3, 2 ) =3D=3D 9 =3D=3D 3^2 Does that help? On 10/30/05, Scott <fre...@ve...> wrote: > >It looks to me like you want this: > > >Power =3D Weight / pow((ET / 5.825), 3); > > Yes, thanks to all of you that did the trick..... > Now i'll just have to understand why that works... > > I'm glad i'm not sending people to the Moon..:) > > Thanks to everyone, for their prompt and helpful > replies, it really makes trying to learn this crap, > far more tolerable, with the excellent and quick help > from you guys..... I do appreciate it.. > > Thanks again.... > > Cheers, > Scott. > > > > > > ------------------------------------------------------- > This SF.Net email is sponsored by the JBoss Inc. > Get Certified Today * Register for a JBoss Training Course > Free Certification Exam for All Training Attendees Through End of 2005 > Visit http://www.jboss.com/services/certification for more information > _______________________________________________ > Dev-cpp-users mailing list > Dev...@li... > TO UNSUBSCRIBE: http://www23.brinkster.com/noicys/devcpp/ub.htm > https://lists.sourceforge.net/lists/listinfo/dev-cpp-users > -- Cheers, Josh |