Re: [Dev-C++] Translation

&ulRandomNum is the adress of ulRandomNum (You don't give us the definition 
of it, so don't know what it is)
(char *) is a cast. It makes the adress of ulRandomNum be read as a char 
array. So ((char *) &ulRandomNum) [nIndex]
will give you a byte of the binary code of ulRandomNum.
Wobien

----- Original Message ----- 
From: "Szentpali Janos" <ia...@ea...>
To: <dev...@li...>
Sent: Monday, January 07, 2008 6:32 PM
Subject: [Dev-C++] Translation


Hi,

I am very new to C++. I only did VB programming... mostly. I am having
some trouble with some C++ code. Could someone help me understand what
the following means:

   --- start ---

   typedef DWORD(*FUNCPTR)(BYTE);

   DWORD  ulWorkRandomNum;
   char  *arr;
   int    nIndex;

   ...

   arr [2 * nIndex] = 'A' + (((char *) &ulRandomNum) [nIndex] & 0x0f);

   --- end ---

I am having trouble with "translating" (understanding) the

    ((char *) &ulRandomNum) [nIndex]

part. I mean [nIndex] referes to the elemnt of which array :O

-- 
Szentpáli János


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