[Dev-C++] SAME MESSAGE BUT 4k IN FILE SIZE NOT 14k Fw: Char datatype

deeps6ix

         Well, even though other estimeed members have already answered
this, let me explain why char is case-sensitive; I kinda get the feeling, by
your question, you do not fully understand what a char is.
         The datatype 'char' is a "virtual conception", in that a 'char' = 1
byte, and represents an entry of ASCII table.
         The 'char' type does not exist in terms that it is really a
integer.
         Every entry of the ASCII table features a value and a charater. the
first 31 entries consist of teletype control codes, like carriage return
 legacy typewriter thing, that you had to do when you wanted to change
lines. )
         The following 96 entries features common letters, numbers and
pontuaction stuff.
         This, obviously represents the first 127 entries, that are, also
the maximum value a byte ( signed ) can achive...
         but looking into ASCII table reveals Value('M') = 77 and Value('m')
= 109, therefore 'm' != 'M'

Check out this code, execution gives more info :

<CODE LANG="C">
#include <stdio.h>
int ReturnBytesInChar( unsigned char ch )    {
    /* Right shhifts bits out, to AND with 0000 0001*/
    int i;
    for ( i=7*sizeof( char ) ; i >=0 ; i-- )
      printf("%d", (ch >> i) & 1 );
}
int ReturnBytesInInt( unsigned int ch )    {
    int i;
    for ( i=7*sizeof(int) ; i >=0 ; i-- )
      printf("%d", ( ch >> i ) & 1);
}
int main ()       {

   char a = 'a';
   unsigned int  aIntegerValue = 97;
   unsigned int Draw;
   printf("Is a char = \'a\' equal a int = 97?\n\n");
   if ( a == aIntegerValue )
      printf("Wow, they do ? WTF!");
   else
      printf("Nah! this guys is full of bollogny"); // This will never
happen!!! heheh humor, hehe
   printf ("\n\nBut.. numbers of bytes allocatted for a char variable are %d
and for a integer one %d\n...How can this be?", sizeof(char),sizeof(int));
   printf("\n\nSimple dude :\n Check this table :\n");
   for ( Draw^=Draw ; Draw != 9+sizeof(int)*7; Draw ++ ) putchar('-');
   printf("\n\nChar bytes\t:\t%d\nVarDump:", sizeof( char ) );
   ReturnBytesInChar( a );
   printf("\n\nInt var bytes\t:\t%d\nVarDump:", sizeof( int ) );
   ReturnBytesInInt( aIntegerValue );
   putchar(10);
   for ( Draw^=Draw ; Draw != 9+sizeof(int)*7; Draw ++ ) putchar('-');
   printf("\nNotice the similarities ? from the %do byte to the %do of
integer the value equals \rchar's %d byte%c\n", sizeof(unsigned int)-1,
sizeof(unsigned int), sizeof(char), (sizeof(char)>1) ? 's':' ');
   printf("What about diferent capitalizations? \'m\' and \'M\'?\nComputer
see them as their values, and not letters...\n");
   printf("See it as :\n\n\tAs value(\'m\') != value(\'M\')
=>(implies)\n\t\t 'M' != 'm' \nAnd we can see it by the same functions
above...");
   printf("mess with them, and learn... and \rsee functions like fgetc() and
try to understand why they are \'buggy\'");
   scanf("%c",&a);
}
</CODE>





Date: Sat, 29 Mar 2008 11:20:28 +1200
From: dee...@gm...
To: dev...@li...
Subject: [Dev-C++] Char datatype

hello all,
i would like to know if the CHAR datatype is case-sensitive??
i.e. should i write code like this to recognise the character or not

e.g.
char = category;
if (category == 'M') or (category == 'm')

cheers..

--
---Deepesh Kapadia---



Veja mapas e encontre as melhores rotas para fugir do trânsito com o Live
Search Maps! Experimente já!



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